Wednesday 07 April 2010 2:53:26 am

Hi Edwidge,

just alter an existing content-class (or create a new one) and add a file attribute to it (name it for example xml_file).

Create a contentobject from this class and upload the xml-file to the xml_file attribute.

Than you can acess the full path to the xml-file in a template by first fetching the content object and than accessing the xml_file attribute via the objects data_map.

(In this example the content_object is assigned to node_id 100, the name of the file attribute is xml_file)

{def $myFileObject = fetch( 'content', 'node', hash( 'node_id', 100))}

{def $myFileURL = $myFileObject.data_map.xml_file.content.filepath|ezroot}

{* Now use it in your javascript *}
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" type="text/javascript"></script>
<script type="text/javascript">
var xmlfile = '{$myFileURL}';
{literal}
$(document).ready(function()
{
     $.ajax({
       type: "GET",
       url: xmlfile,
           dataType: "xml",
           success: doSomethingWithXML
    });
});
doSomethingWithXML = function( data )
{
    // your code to deal with the xml
}
{/literal}

Hope you got the idea.

Best regards,

Patrick

Tuesday 13 April 2010 3:17:40 am

Hi Edwige,

Good to read you got a solution to your problem :)
You may now want to mark the topic as solved (small ticker at the left of the topic's title above).

Cheers,

--
Nicolas Pastorino
Director Community - eZ
Member of the Community Project Board

eZ Publish Community on twitter: http://twitter.com/ezcommunity

t : http://twitter.com/jeanvoye
G+ : http://plus.tl/jeanvoye