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Ez Publish 4.3 Design Configuration

Ez Publish 4.3 Design Configuration

Wednesday 01 September 2010 6:47:27 am - 3 replies

Author Message

André R.

Wednesday 01 September 2010 9:23:00 am

your better of using a different class, for instance folder, frontpage is meant to cover the whole width, lots of css and code that you will have to fight.

Use advance -> swap node from context menu (the one on icons) in admin to change object of root node to something else.

As for getting things to show up in left menu, well, the children are shown in top menu I guess?
So to customize something for left menu, use your own left menu by setting a string (name of template within menu folder without ".tpl" suffix) on 'left_menu' instead of "true()".

for templates/menu/frontpage_left_menu.tpl:

{set scope=global persistent_variable=hash('left_menu', 'frontpage_left_menu',

eZ Online Editor 5: http://projects.ez.no/ezoe || eZJSCore (Ajax): http://projects.ez.no/ezjscore || eZ Publish EE http://ez.no/eZPublish/eZ-Publish-Enterprise-Subscription
@: http://twitter.com/andrerom

Eric Handler

Wednesday 01 September 2010 1:08:08 pm

I'm an Ez Publish newbie, so most of my progress has been trial and error based on all the documentation that says copy ezwebin and modify that.

I am not sure I follow your instructions. I swapped root to make it a folder rather than a front page. At this point I don't quite get what you are suggesting so I have tried to explain what I am trying to do

For Home I want to have the left menu duplicate the "Products", "About Us", "Careers" links that appear in the top menu as they are the three nodes (Class=Frontpage) inside the root folder. However, when I navigate to "About Us" I would like to have it show the sub pages of "About Us" which are articles about each employee on the side menu. Does this clarify what I am attempting to do?

Additionally, creating the new site has made me realize that I am having a hard time finding documentation about creating and modifying templates, any suggestions on where to find some helpful guides on creating custom classes and templates to define the appearance of those new classes?

Anaya P

Friday 10 September 2010 8:15:34 am

hopefully I have understood you right. You need to change page_leftmneu.tpl. Try below code and if this is what you want, then create your custom extension and override page_leftmenu.tpl(with below content) in there.

<code>

<div id="sidemenu-position">
<div id="sidemenu">
{if $module_result.content_info.class_identifier|eq('frontpage')}

{if is_array( $pagedata.left_menu )}
{foreach $pagedata.left_menu as $left_menu}
{include uri=concat('design:menu/', $left_menu, '.tpl')}
{delimiter}
<div class="hr"></div>
{/delimiter}
{/foreach}
{else}
{include uri=concat('design:menu/', $pagedata.left_menu, '.tpl')}
{/if}

{else}

{def $sub_menu=treemenu($module_result.path, $module_result.node_id,
array('standard_page','folder','contact_form','sub_page','link', 'frontpage', 'global_layout'), 1, 3) }
<div class="border-box">
<div class="border-tl">
<div class="border-tr">
<div class="border-tc"></div>
</div>
</div>
<div class="border-ml">
<div class="border-mr">
<div class="border-mc">
{if eq( $module_result.node_id, 2 ) }
{let $tmp_root_node=fetch( content, node, hash( node_id, 2 ) )}
<h4>{$tmp_root_node.name}</h4>
{/let}
{else}
<h4>{$module_result.path[1].text}</h4>
{/if}
<ul class="menu-list">
{def $last=0}
{foreach $sub_menu as $s_menu}
{if and($last|ne(0), $last.level|gt($s_menu.level))}{* this if second level is open *}
</ul>
</li>
{/if}
<li> {if and($last|ne(0), $last.level|lt($s_menu.level))}{* this if there is no second level *}
<ul>
<li>{/if}<a {if $s_menu.is_selected} class="current"{/if} href={$s_menu.url_alias|ezurl}>{$s_menu.text}</a></li>
{set last=$s_menu}
{/foreach}
</ul>
{undef $last}
{undef $sub_menu}
</div>
</div>
</div>
<div class="border-bl">
<div class="border-br">
<div class="border-bc"></div>
</div>
</div>
</div>
{/if}
</div></div>

</code>

As you will notice in above code, there is an array of class name defined, so if you want any of the page to appear in the left column, you need to add class name for that page in that array, for your reference below is the code -

<code>

{def $sub_menu=treemenu($module_result.path, $module_result.node_id,
array('standard_page','folder','contact_form','sub_page','link', 'frontpage', 'global_layout'), 1, 3) }

</code>

Hope this helps!

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